60x^2-95x-20=0

Solution for 60x^2-95x-20=0 equation:

60x^2-95x-20=0

a = 60; b = -95; c = -20;
Δ = b2-4ac
Δ = -952-4·60·(-20)
Δ = 13825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13825}=\sqrt{25*553}=\sqrt{25}*\sqrt{553}=5\sqrt{553}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-5\sqrt{553}}{2*60}=\frac{95-5\sqrt{553}}{120}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+5\sqrt{553}}{2*60}=\frac{95+5\sqrt{553}}{120}
$